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A loudspeaker diaphragm is oscillating in simple harmonic motion with a frequency of 379 Hz and a maximum displacement of 0.562 mm. What are the (a) angular frequency, (b) maximum speed, and (c) magnitude of the maximum acceleration

User Tzane
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Answer:

f = 379 / s given

A) ω = 2 pi f = 2380 / sec

B) Vmax = ω A = 2380 / sec * .000562 m = 1.34 m.s

C) amax = -ω^2 A = -(2380)^2 * .000562 = -3180 m/s^2

User Sunghoon
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