Question

A stone is thrown vertically upward with velocity 9.8ms 1)calculate the time taken to reach maximum height.2)what is the maximum height reached 3) what is time taken to reach ground 4)what velocity it reaches the ground

Answer 1

It would take 6 seconds before hitting the ground

Step-by-step explanation:

Answer 2

1.t=-1.96sec

2.H=4.8m

3.T=1.96sec

4.R=19.2m

Step-by-step explanation:

u=9.8,t=?,sin theta=1

using formula t=2usintheta/g

t=2x9.8x1=19.6/10

t=1.96seconds

using formula H=u(squared)sin(squared)theta/2g

H=9.8(squared)x1(squared)/2x10

H=96x1/20

H=96/20

H=4.8m

using formula T=2usintheta/g

T=2x9.8x1/10

T=19.6/10

T=1.96sec

using the formula R=u(squared)sin2theta/g

R=9.8(squared)x2/10

R=96x2/10

R=192.08/10

R=19.2