Question

I need help please! I'm stumped and I don't know what to do.

Answer 1

Here,

3y-49=0----------(i)

x^2+y^2-281=0----------(ii)

from eqn (i)

y=49/3

Now,substituting value of y in eqn (ii)

x^2+(49/3)^2-281=0

or,x^2+2401/9-281=0

or,9x^2+2401-2529=9×0

or,9x^2=128

or,x^2=128/9

therefore,

x=8√2/3

Hope it helps...