Question

ABCD, EFGH, and HIJK are squares.

AABCD = 400 cm2, O is the center of the circle, O ∈
FE
,
FG
and
BC
tangent to the circle (see the picture on the right).

Find the length of
AM
.

Answer 1

40/3 cm

Explanation:

FE : DC

1 : 3

Since area ABCD = 400

s² = 400

s = 20

FE = ⅓(20) = 20/3 cm

AM = DC - FE

AM = 20 - 20/3 = 40/3