Question

- Calculate the efficiency of the human body if a person eats a hamburger containing 7.4822 kJ of

energy and the body uses 2021 J of energy for its necessary life processes,
A. 3.702%
B. 27.01%
C. 35.00%
D. 100.0%

Answer 1

w = E
efficiency = (Woutput /Winput) x 100%= Eo/Ei x100%
= (2021 j / 7.4822 kj) x 100%
= 27.01% == B

Answer 2

Step-by-step explanation:

w = E

efficiency = (Woutput /Winput) x 100%= Eo/Ei x100%

= (2021 j / 7.4822 kj) x 100%

= 27.01% == B