Question

Help me find Angle BAD

Answer 1

We have parallelogram ABCD and isosceles triangle ADE, with equal angles ∠ADE = ∠AED.

∠ADE + ∠AED + ∠EAD = 180°

2 ∠ADE + 52° = 180°

∠ADE = (180° -52°) / 2 = 64°

∠ADE and ∠BAD are alternate interior angles of a transversal through parallel lines, so they're congruent. So ∠BAD is

Answer: 64°

Answer 2

BAD = 64°

Explanation:

ADE = (180-52):2 = 64°

ED || AB => ADE = BAD = 64°