Question

When potassium chlorate decomposes it produces potassium chloride and oxygen gas. If 223.65 g of potassium chloride was produced, how much potassium chlorate did the reaction start with?

Answer 1

367.7466 g of potassium chlorate is produced.

Step-by-step explanation:

Given data:

223.65 g of potassium chloride is produced

Question: How much potassium chlorate did the reaction start with, mKClO₃ = ?

The balanced reaction:

2KClO₃ → 2KCl + 3O₂

Information needed:

Molecular weight of KClO₃ = 122.5 g/mol

Molecular weight of KCl = 74.5 g/mol

Molecular weight of O₂ = 32 g/mol

You can see in the reaction that 2 moles of KClO₃ gives 2 moles of KCl.

Mass of KClO₃:

`m_{KClO_(3) } =2*122.5=245g`

Mass of KCl:

`m_(KCl ) =2*74.5=149g`

245 g KClO₃ --------- 149 g KCl

X g KClO₃ ------------- 223.65 g KCl

`X=m_{KClO_(3) } =(245*223.65)/(149) =367.7466g`