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Which of the following is equivalent to the complex number i^35

User Sir Mbuki
by
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1 Answer

7 votes

Answer:

-i

Explanation:

The imaginary unit i is defined by the property that
i^2=-1. With that in mind, we can list the first few powers of i:


i^0=1\\i^1=i\\i^2=-1\\i^3=-i\\i^4=1

Notice how
i^0 is the same as
i^4? The powers of i are cyclic: they repeat every 4 powers. In general, for any power of i
i^n:


i^n=1 if
n/4 has remainder 0


i^n=i if
n / 4 has remainder 1


i^n=-1 if
n/4 has remainder 2


i^n=-i if
n/4 has remainder 3


35/4=8R3, so
i^(35)=-i

User Dmitry Grushin
by
5.9k points