Answer:
tan(K) = 9/40
Explanation:
You have a right triangle KLM with side ML = 9 (opposite angle K) and KM = 40 (adjacent to angle K). You want to know the tangent ratio for angle K.
Tangent
The mnemonic SOH CAH TOA is intended to remind you that the tangent of an acute angle in a right triangle is ...
Tan = Opposite/Adjacent
Application
The tangent of angle K is the ratio ...
tan(K) = LM/KM
tan(K) = 9/40