Question

Imagine that you just solved a quadratic equation and got -3 and 3 as your answers. Give a scenario in which -3 would not be possible to be a solution. *

Answer 1

The growth rate of a tree

Explanation:

Here, we are asked in what situation when solving a quadratic equation and our answers are -3 and 3 in which -3 would mot be a possible solution.

Where the quadratic equation of which the solution is -3 pertains to items which only have positive values, such as "the number of persons" or "things" or the "time duration" of an event, then the -3 would not be a possible solution.

Example, a function of time, such as velocity, with a solution of

(x-3)(x+3) then the -3 will not be a possible solution.

Another example is the growth rate of a tree given by

(t-3)(t+3) = 0.

Answer 2

The quadratic equation
`x^(2) + 6x + 9 = 0` would have a value of x = + 3 (twice)

Explanation:

If x = ± 3. then x = +3 or x = -3

The quadratic equation would be:

(x + 3) (x +3) = 0

`x^(2) - 9 = 0`

For x ≠ -3, the equation would be:

`x^(2) + 6x + 9 = 0`, where x = + 3 (twice).