54.1k views
0 votes
How do you solve: 7^2=12^x

2 Answers

6 votes

Answer:

x ≈ 1.57

Explanation:

First, note that 7^2 equals 7 * 7 = 49. Now, we have:

49 =
12^x

In order to solve for x, we need to use logarithm, which basically "gets rid of" the exponent. What we need to do is take the
log_(12) of each side. Notice that the base of the logarithm is 12. This is because we want to cancel out the exponent base of 12 on the right side:


log_(12)49=log_(12)12^x


log_(12)49=x

So, x ≈ 1.57.

Hope this helps!

User Thebernardlim
by
7.4k points
4 votes

Answer:

x = 1.566

Explanation:

7^2=12^x

  • 7^2 means 7 squared, which is 7*7, which is 49.

49 = 12^x

  • Now we have to use logarithms to figure this out! Logarithms are like the opposite of exponents.

Exponential: b^x = y

Logarithmic: logb(y) = x.

  • B stands for base.
  • Now with 49 = y, 12 = b, we plug in to get x:

logb(y) = x

log12(49) = x

Plug this in your calculator (on a TI-84, it's MATH -> A)

x = 1.566

User Stephen Olsen
by
7.6k points