54.1k views
0 votes
How do you solve: 7^2=12^x

2 Answers

6 votes

Answer:

x ≈ 1.57

Explanation:

First, note that 7^2 equals 7 * 7 = 49. Now, we have:

49 =
12^x

In order to solve for x, we need to use logarithm, which basically "gets rid of" the exponent. What we need to do is take the
log_(12) of each side. Notice that the base of the logarithm is 12. This is because we want to cancel out the exponent base of 12 on the right side:


log_(12)49=log_(12)12^x


log_(12)49=x

So, x ≈ 1.57.

Hope this helps!

User Thebernardlim
by
8.1k points
4 votes

Answer:

x = 1.566

Explanation:

7^2=12^x

  • 7^2 means 7 squared, which is 7*7, which is 49.

49 = 12^x

  • Now we have to use logarithms to figure this out! Logarithms are like the opposite of exponents.

Exponential: b^x = y

Logarithmic: logb(y) = x.

  • B stands for base.
  • Now with 49 = y, 12 = b, we plug in to get x:

logb(y) = x

log12(49) = x

Plug this in your calculator (on a TI-84, it's MATH -> A)

x = 1.566

User Stephen Olsen
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories