Question

I need help ASAP please (solving rational equations)

Answer 1

`1 - (y-1)/(y) = (1)/(y^2 + 2y)`

`\frac y y - (y-1)/(y) = (1)/(y^2 + 2y)`

`(1)/(y) = (1)/(y^2 + 2y)`

`y = y^2 + 2y`

`y^2 + y = 0`

`y(y+1)=0`

`y = 0 \textrm{ or } y = -1`

We rule out y=0 because of the denominator y in the original equation.

Answer: B: y=-1