Answer:
Series equivalent resistance:
Parallel equivalent resistance:
![R_(eq)=14\Omega](https://img.qammunity.org/2021/formulas/physics/middle-school/vyjcamn2ht3soal62smwhll4h9f1jtfapw.png)
Step-by-step explanation:
The equivalent resistance in series circuit is calculated as
![R_(eq) = R_(1) + R_(2)](https://img.qammunity.org/2021/formulas/physics/middle-school/771nn1rnzd5zhcdtfyw0bkmz04fec54fa8.png)
![R_(eq) = 2 + 4](https://img.qammunity.org/2021/formulas/physics/middle-school/a5l4760lc39fydr2xc8f2okg9o54zm4n24.png)
![R_(eq) = 6 \Omega](https://img.qammunity.org/2021/formulas/physics/middle-school/hwaebrhmjr49rwcg3wivf1mtnrl6lnpls7.png)
The equivalent resistance in parallel circuit is calculated as
![(1)/(R_(eq)) = (1)/(R_(1))+(1)/(R_(2))](https://img.qammunity.org/2021/formulas/physics/middle-school/jfhnp8ufa5qxhwv0w7z8sgap2woyd405ax.png)
Which can be simplified to
![R_(eq)=(R_(1)* R_(2))/(R_(1)+R_(2))](https://img.qammunity.org/2021/formulas/physics/middle-school/m8a19prkfqpkfrrkrkbcdqyngkhg7qqgjv.png)
![R_(eq)=(21* 42)/(21+42)](https://img.qammunity.org/2021/formulas/physics/middle-school/eqjnu2qix2mol3a96ptqydz55273ganevk.png)
![R_(eq)=14\Omega](https://img.qammunity.org/2021/formulas/physics/middle-school/vyjcamn2ht3soal62smwhll4h9f1jtfapw.png)
The parallel circuit has the higher equivalent resistance as compared to series circuit.