Question

What is a change in heat energy when 40 g of water at 25°C is raise to 60°C

Answer 1

0.588J

Step-by-step explanation:

m=40g to Kg divide by 1000

40/1000=0.004kg, c=4.2,change in temperature = 60-25=35

Q=mxcx change in theta

Q=0.004x4.2x35

Q=0.588J