Question

What is the area of a regular pentagon with side length 10 ft?

And please explain how you did it!! Ty

Answer 1

The answer is about 172.05
`ft^(2)`

Explanation:

Area Formula for a Pentagon:

A=
`(1)/(4)`
`\sqrt{5(5+2\sqrt[]{5 } )`
`a^(2)`

A=
`(1)/(4)`
`\sqrt{5(5+2\sqrt[]{5 } )` (10ft)^2

A= 172. 05
`ft^(2)`