Question

A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

Answer 1

Answer:
`P=(4)/(15)`

Explanation:

Given

Bag contains 4 yellow marble and 6 green marble

If the marble is not replace after the first withdrawal

Probability that the first marble is green and the second one is yellow

`P(1)=`Choosing first marble as green out of 10 marble

`P(2)=`Choosing second marble as yellow out of 9 marble

`P=P(1)* P(2)`

`P=(^6C_1)/(^(10)C_1)* (^4C_1)/(9^C_1)`

`P=(4)/(15)`