Answer: 300
Explanation:
Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.
i.e, Total CD's he has now = 6,000
Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.
Then , the proportion of defective( D) CD's =
![(D)/(S)=(2)/(40)=0.05](https://img.qammunity.org/2021/formulas/mathematics/high-school/4gmbem9vygk5s6xq573kope0vdrpoyzfif.png)
Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)
= 6000 x 0.05
=300
Hence, the number of CDs in the shipment are likely to be defective =300