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What is the area of one of the triangular faces? —In.2

What is the area of one of the triangular faces? —In.2-example-1
User Lucataglia
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2 Answers

4 votes

Answer:

6 inches squared

Explanation:

Edgen uity is hard but not for me

User Vimukthi
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8.2k points
1 vote

Answer:

6 inches squared

Explanation:

The triangle is a right triangle. We can see this because it is attached a rectangle, which has angles of 90 degrees.

Now, notice that the hypotenuse is given as 5 inches and one of the legs is given as 3 inches. We can use the Pythagorean Theorem to find the third side: x =
√(5^2-3^2) =√(25-9) =√(16) =4

The area of a triangle is A = (1/2) * b * h, where b is the base and h is the height perpendicular to the base. We know the base is 3, so b = 3, and we also see that the height is 4, so h = 4. Plugging these in:

A = (1/2) * b * h = (1/2) * 3 * 4 = 6

Thus, the area of one of the triangular faces is 6 inches squared.

Hope this helps!

User Conal
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