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Consider a balloon that has a volume V. It contains n miles of gas, It has an internal pressure of p , and it's temperature is T. If the balloon is heated to a temperature of 15.5P while it is placed under a high pressure of 15.5P, Does the volume of the balloon change?

User Arshiya
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1 Answer

3 votes

Answer:

The volume didn't change

Step-by-step explanation:

Step 1: Data given

Volume of a balloon = V

Moles of gas = n

Temperature in the balloon = T

Pressure in the balloon = P

The temperature is heated to 15.5 T

The pressure in the balloon is increased to 15.5 P

Step 2: Calculate the new volume

(P1*V1) / T1

Volume is V

(P2*V2)/T2

⇒with P2 = 15.5 P

⇒with V2 = TO BE DETERMINED

⇒with T2 = 15.5 T

V2 = (P1 * T2 * V1) / (T1 * P2)

V2 = (1*15.5 * 1) / (1* 15.5)

V2 = 1

The volume didn't change

User Julio Cachay
by
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