Question

What is the length of the hypotenuse of the triangle?

Answer 1

AB²=AC²+ BC²

`AB = \sqrt{ {(8)}^(2) + {(15)}^(2) }`

`= √(64 + 225) = √(289) = 17`

AB(hypotenuse)=17cm

Answer 2

Explanation:

Here Given

perpendicular (p)= 15 cm

base (b) = 8 cm

hypotenuse (h) = ?

We know by using Pythagoras theorem,

`h^(2) =p^(2) +b^(2)`

`h^(2) = 15^(2) + 8^(2)`

`h^(2) = 225 +64`

`h^(2) = 289`

`h =√(289)`

Therefore h = 17 cm

Hope it will help :)