Answer:
(1) The moles of H+(aq) equal the moles of OH-(aq).
Step-by-step explanation:
Statements are:
(1) The moles of H+(aq) equal the moles of OH-(aq).
(2) The moles of H2SO4(aq) equal the moles of NaOH(aq).
(3) The moles of H2SO(aq) are greater than the moles of NaOH(aq).
(4) The moles of H+(aq) are greater than the moles of OH-(aq).
Neutralization reaction of H₂SO₄ with NaOH is:
H₂SO₄ + 2 NaOH → 2H₂O + Na₂SO₄
Where 1 mole of sulfuric acid (2 moles H⁺), reacts with 2 moles of NaOH (2moles of OH⁻)
As you cans see, the reaction occurs when moles of H⁺ are equal to moles of OH⁻
In the problem, moles of H⁺ are:
0.010L ₓ (0.50moles H₂SO₄ / 1L) ₓ (2moles H⁺ / mole H₂SO₄) =
0.01 moles of H⁺
Moles of OH⁻ are:
0.005L ₓ (2.0moles NaOH / 1L) ₓ (1mole OH⁻ / mole NaOH) =
0.01 moles of OH⁻
Thus, right statement is:
(1) The moles of H⁺(aq) equal the moles of OH⁻(aq).