Answer:
The 99% confidence interval for mean is (0.9551, 0.9569).
Explanation:
The (1 - α)% confidence interval for the population mean is:
![CI=\bar x\pm z_(\alpha/2)\ (\sigma)/(√(n))](https://img.qammunity.org/2021/formulas/mathematics/college/clkkgut7kusp2a1mv30u4rny89uw08guth.png)
The information provided is:
![n=33\\\bar x=\mu=0.956\\\sigma=0.002\\(1-\alpha) \%=99\%](https://img.qammunity.org/2021/formulas/mathematics/college/ixnycoohhm1069pkoanw7hw7ec6ujc869g.png)
The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (
) approaches the whole population mean (µ).
In this case the sample size is quite large, i.e. n = 33 > 30. So, according to the law of large numbers, the sample mean is approximately same as the population mean.
The critical value of z for 99% confidence level is:
![z_(\alpha/2)=z_(0.005)=2.58](https://img.qammunity.org/2021/formulas/mathematics/college/5wa16qnodgfeslisputdgcbkm91m71ngc4.png)
*Use a z-table.
Compute the 99% confidence interval for mean as follows:
![CI=\bar x\pm z_(\alpha/2)\ (\sigma)/(√(n))](https://img.qammunity.org/2021/formulas/mathematics/college/clkkgut7kusp2a1mv30u4rny89uw08guth.png)
![=0.956\pm 2.58* (0.002)/(√(33))\\=0.956\pm 0.0009\\=(0.9551, 0.9569)](https://img.qammunity.org/2021/formulas/mathematics/college/2hvsvio90dxeko91ri7a310jb4wfxfk1aj.png)
Thus, the 99% confidence interval for mean is (0.9551, 0.9569).