Question

A sample of water with a mass of 622.7g undergoes a temperature change from 90.98°C

to 96.70°C. What is the heat change in Joules? Cwater=4.18J/g°C


A)0251608.10
B)3561.8J
C)14888.5)
D)2.51X105)

Answer 1

C) Q = 14888.5 J

Step-by-step explanation:

• Q = mCΔT

∴ m H2O = 622.7 g

∴ C H2O = 4.18 J/g°C

∴ ΔT= 96.7°C - 90.98°C = 5.72°C

⇒ Q = (622.7 g)(4.18 J/g°C)(5.72°C)

⇒ Q = 14888.508 J