Question

An 80kg student running at 3.50m/s grabs a rope that is hanging vertically. How high will the student swing?

Answer 1

The student will swing to a height of 61.25 cm.

Step-by-step explanation:

Given that,

Mass of the student, m = 80 kg

Speed of student, v = 3.5 m/s

The student running at this speed grabs a rope that is hanging vertically. In the whole process, the energy of the system remains conserved. So, using conservation of energy to find the height reached by the student. So,

`(1)/(2)mv^2=mgh`

h is height reached by the student

`h=(v^2)/(2g)\\\\h=((3.5)^2)/(2* 10)\\\\h=0.6125\ m\\\\h=61.25\ cm`

So, the student will swing to a height of 61.25 cm.