What is the concentration of hydroxide in a solution with a pOH of 9.8? ph+pOH=14 [OH-]=10^-pOH

asked Dec 12, 2021 60.4k views

1 vote

What is the concentration of hydroxide in a solution with a pOH of 9.8?

ph+pOH=14 [OH-]=10^-pOH

by Vogdb

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2 votes

Answer:

1.6*10^(-10) M

Step-by-step explanation:

pOH = 9.8

[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)

Ben Scarberry answered Dec 17, 2021

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