Question

"How many formula units are there in sample of copper(II) sulfate that has

a mass of 32.5 grams?" *
8.16E(-24) formula units CuSO4
O
1.23E23 formula units CuSO4
O
3.38E(-25) formula units Cus04
2.96E24 formula units CuSO4

Answer 1

Answer:
`1.23* 10^(23)` formula units

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(32.5g)/(160g/mol)=0.203moles`

1 mole of
`CuSO_4` contains
`6.023* 10^(23)` of formula units

Thus 0.203 mole of
`CuSO_4` contains =
`(6.023* 10^(23))/(1)* 0.203=1.23* 10^(23)` of formula units