Question

Choose the equation below whose axis of symmetry is x = 0. (1 point) Group of answer choices y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2 − 4x + 2

Answer 1

`(C)y = x^2 +2`

Explanation:

Given the general form of quadratic equation
`ax^2+bc+c=0`, the axis of symmetry is derived using the equation
`x=-(b)/(2a)`

Given the equation

`y = x^2 + 2x\\a=1, b=2\\Axis of Symmetry, x=-(2)/(2(1))=-1`

Next,

`y = x^2 -16x+58\\a=1, b=-16\\$Axis of Symmetry$, x=-(-16)/(2(1))=8`

Next,

`y = x^2 +2\\a=1, b=0\\$Axis of Symmetry$, x=-(0)/(2(1))=0`

Lastly,

`y = x^2 -4x+2\\a=1, b=-4\\$Axis of Symmetry$, x=-(-4)/(2(1))=2`

Clearly,
`y = x^2 +2` is the equation whose axis of symmetry is x=0.