Answer:
D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.
Explanation:
We will test the hypothesis on the difference between means.
We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).
Then, the difference between means is:
![M_d=M_1-M_2=18.2-15.9=2.3](https://img.qammunity.org/2021/formulas/mathematics/college/qin464o24mvneee26vivinzt003d925vnv.png)
If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:
![t=(M_d-(\mu_1-\mu_2))/(s_(M_d))=(2.3-(0))/(1.1)=2.09](https://img.qammunity.org/2021/formulas/mathematics/college/8czfb52nrua5fynuy34l1j1hj8a2we3eed.png)
The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.
This is approximately 2 standards deviation (z=2).
The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.