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If a container has a volume of 8.00 L of helium at 20.0oC and a pressure at 3.0 atm, what is the new temperature of this gas when the volume is 4.3 L at a pressure of 1.2 atm?
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If a container has a volume of 8.00 L of helium at 20.0oC and a pressure at 3.0 atm, what is the new temperature of this gas when the volume is 4.3 L at a pressure of 1.2 atm?

User Bogdan Verbenets
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1 Answer

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P1V1/T1 = P2V2/T2

T2 = P2V2T1/P1V1

= 1.2*4.3*20/3*8 = 4.3

User Joshua Sullivan
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