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For alln∈N≥1(son≥1), and usingweakinduction, prove that:n∑i=1i3=[n(n+ 1)2]2Note that this result means that the sum of the third powers of the first strictly positive integers is equal to the sum of the same integers, squared=

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Answer:

Explanation:

hello,

the question is not really clear. i believe the intended equation would be


\sum_(k=1)^(k=n) k^3=((n(n+1)))/(4)

please check the attached file for the step by step proof.

For alln∈N≥1(son≥1), and usingweakinduction, prove that:n∑i=1i3=[n(n+ 1)2]2Note-example-1
For alln∈N≥1(son≥1), and usingweakinduction, prove that:n∑i=1i3=[n(n+ 1)2]2Note-example-2
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