Answer:
See explaination
Step-by-step explanation:
public class StringLab9 {
public static void main(String args[]) {
char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };
String s1 = new String("Objected oriented programming language!");
String s2 = "COSC 3317 OO class class";
String s3 = new String(charArray);
// To do 1: print out the string length of s1
System.out.println(s1.length());
// To do 2: loop through characters in s2 with charAt and display reversed
// string
for (int i = s2.length() - 1; i >= 0; --i)
System.out.print(s2.charAt(i));
System.out.println();
// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)
// is
// greater than which string (s2 or s3), or equal, print the result out
if (s2.compareTo(s3) == 0)
System.out.println("They are equal");
else if (s2.compareTo(s3) > 0)
System.out.println("s2 is greater");
else
System.out.println("s3 is greater");
// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of
// the first 8 characters.
// and print out the result (match or not) .
if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)
System.out.println("They matched");
else
System.out.println("They DONT match");
// To do 5: Find the location of the first character 'g' in s1, print it out
int i;
for (i = 0; i < s2.length(); ++i)
if(s2.charAt(i)=='g')
break;
System.out.println("'g' is present at index " + i);
// To do 6: Find the last location of the substring "class" from s2, print it
// out
int index = 0, ans = 0;
String test = s2;
while (index != -1) {
ans = ans + index;
index = test.indexOf("class");
test = test.substring(index + 1, test.length());
}
System.out.println("Last location of class in s2 is: " + (ans + 1));
// To do 7: Extract a substring from index 4 up to, but not including 8 from
// s3, print it out
System.out.println(s3.substring(4, 8));
} // end main
} // end class StringLab9