Question

Hot-air balloons rise because the hot air inside the balloon is less dense than the cooler air outside. Calculate the volume an air sample will occupy inside a balloon at 43.0C if it occupies 2.50L at the outside air temperature of 22.0C, assuming the pressure is the same at both locations

Answer 1

`V_2=2.68L`

Step-by-step explanation:

Hello,

In this case, we use the Charles' law which allows us to understand the volume-temperature behavior as gas has as a directly proportional relationship:

`(V_1)/(T_1)=(V_2)/(T_2)`

Whereas the temperature must be in absolute units such as Kelvin. Hence, solving for the volume at 43.0 °C, we obtain:

`V_2=(V_1T_2)/(T_1)=(2.50L*(43.0+273.15)K)/((22.0+273.15)K) \\\\V_2=2.68L`

Best regards.