Question

Last one, I promise!!! ._.

19x+28=20x-53

Answer 1

`{\boxed{\mathfrak{✿ฺSolution :}}}`

`\bold{ 19x+28 = 20 x - 53 }`

`\bold{ 19x+28 - 28 =20x - 53 - 28}`

`\bold{ 19x = 20x - 81 }`

`\bold{ 19x - 20x = 20x - 81 - 20x }`

`\bold{ -x = - 81 }`

`\bold{ ( - x)/( - 1) = ( - 81)/( - 1) }`

`\bold{ x = 81 }`

Answer 2

x = 81

Explanation:

Given:

`\displaystyle \large{19x+28=20x-53}`

Subtract both sides by 28:

`\displaystyle \large{19x+28-28=20x-53-28}\\\displaystyle \large{19x=20x-81}`

Subtract both sides by 19x:

`\displaystyle \large{19x-19x=20x-81-19x}\\\displaystyle \large{0=x-81}`

Add both sides by 81:

`\displaystyle \large{0+81=x-81+81}\\\displaystyle \large{81=x}\\\displaystyle \large{\therefore x=81}`

Therefore, the solution is x = 81

Let me know if you have any questions!