Answer:
Below.
Explanation:
1 / secA+tanA = 1 / [1/cosA+sinA/cosA))]
= 1/ [(1 + sinA)/cosA]
= cosA/(1+sinA)
Now check if this is identical to 1-sinA/cosA:
1-sinA/cosA = cosA/(1+sinA)
Cross multiply:
(1-sinA)(1+sinA) = cos^2A
1 - sin^2A = cos^2A
sin^2A + cos^2A = 1
This is a known idenity.
So the original identity is true.