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Find the sum of the arithmetic series 7+13+...+601.

User Kouk
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1 Answer

1 vote

Answer:

Explanation:

d=13-7=6

Let number of terms=n

l=a+(n-1)d

601=7+(n-1)6

601=7+6n-6

601=6n+1

6n=601-1=600

n=600/6=100


s_(n)=(n)/(2) (a1+an)\\=(100)/(2)(7+601)\\=50 * 608\\=30400

User Nida Amin
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