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What is the pOH of a solution with a [OH^ - ] of 10^ -11?
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What is the pOH of a solution with a [OH^ - ] of 10^ -11?

User Clarisa
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1 Answer

2 votes

Answer:

pOH= 11

Step-by-step explanation:

pOH= -log[10^ -11]= 11

User Wesley Wiser
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