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What is the pOH of a solution with a [OH-] of 10-11
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What is the pOH of a solution with a [OH-] of 10-11

User Jonypz
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1 Answer

3 votes

Answer:

pOH= 11

Step-by-step explanation:

pOH=-log[OH-]

pOH=-log[10^-11]= 11

User Meghdad Hadidi
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