Question

Calculate how many liters of H2 gas at STP are produced from 2.11 moles of aluminum metal.

Answer 1

47.3 L of Hydrogen gas is produced from 2.11 moles of Aluminum metal.

Step-by-step explanation:

We have to find the volume of hydrogen produced by writing the balanced equation as,

2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)

We can use the ideal gas equation at STP,

Temperature = 273.15K

Pressure = 1 atm

Gas constant being 0.08205 L atm K⁻¹ mol⁻¹

Number of moles = 2.11 moles

PV = nRT

Plugin the values as,

`$ V = (nRT)/(P)`

`$V = (2.11 * 0.08205 * 273.15)/(1)`

= 47.3 L

So 47.3 L of Hydrogen gas is produced from 2.11 moles of Aluminum metal.