111k views
3 votes
How many moles of oxygen are in a

7.68 L container at 355 K and exerting a
pressure of 8.57 atm on the walls of the
container?

User GDroid
by
8.3k points

2 Answers

3 votes

Answer:

2.26

Step-by-step explanation:

:)

User Silverdust
by
7.1k points
2 votes
Rearrange the ideal gas law to solve for n :

n = (PV /RT)

= (8.57 atm * 7.68 L) / {[(0.082057 L • atm) / (mol • K)] * 355 K}

= 2.26 moles
User Volody
by
7.3k points