Question

Question:

The surface temperature of the filament in an incandescent light bulb is 1400 ∘C. If we double the current flowing through the light bulb without changing its resistance, what will the surface temperature become?

I'm confused on how to solve this. I thought of using ohm's law but I don't know how it could relate to temperature. Thanks

Answer 1

The surface temperature become 2092.9793°C

Step-by-step explanation:

Given data:

T₁ = surface temperature of the filament = 1400°C = 1673 K

Double the current flowing through the light bulb

Question: What will the surface temperature become, T = ?

Increases the current by the double, increases the heat by four, and the temperature by 4^1/4 too.

`T=T_(1) *(4)^(1/4) =1673*(4)^(1/4) =2365.9793K=2092.9793C`