Question

Help me solve the following question below in the attachment

Answer 1

Step-by-step explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

`E_(1)=(kQ_(1))/(R_(1)^(2))`

`E_(2)=(kQ_(2))/(R_(2)^(2))`

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k =
`k=9* 10^(9)` in
`Nm^(2)/C^(2)`, we can obtain:

`E_(1)=(9* 10^(9))(500*10^(-6))/(25)=180* 10^(3)` N/C (+)

`E_(2)=(9* 10^(9))(100* 10^(-6))/(9)=100* 10^(3)` N/C (-)

So: the Electric Field at P :
`E_(P)=E_(1)-E_(2)=(180-100)* 10^(3)=8* 10^(4)` N/C in magnitude