Question

if exactly 59.6g of dinitrogen monoxide are needed to inflate your air bag to the correct size, how many grams of NH4NO3 would you need to decompose?

Answer 1

108.05 grams of NH4NO3 would you need to decompose to inflate your air bag to the correct size with 59.6g of dinitrogen monoxide.

Step-by-step explanation:

Data given:

mass of dinitrogen monoxide = 59.6 grams

atomic mass of dinitrogen monoxide = 44.01 grams/mole

grams of N
`H_(4)`N
`O_(3)` = ?

atomic mass of ammonium nitrate = 108.05 grams/mole

balanced chemical equation:

N
`H_(4)N_{} O_(3)` ⇒
`N_(2)`O +2
`H_(2)`O

Firstly the number of moles will be calculated from the given mass by using the formula:

number of moles =
`(mass)/(atomic mass of 1 mole)`

putting the values in the equation:

number of moles =
`(59.6)/(44.01)`

number of moles = 1.35 moles

from the balanced equation :

1 mole of ammonium nitrate decomposes to release 1 mole of dinitrogen monoxide

so, 1.35 moles will give 1.35 moles of dinitrogen monoxide.

mass = atomic mass x number of moles

mass = 80.043 x 1.35

mass = 108.05 grams of ammonium nitrate.