Question

g Refer to the Biochemistry in Focus section of your text for this chapter to answer this question. What is the fate of glucose 6-phosphate that enters the pentose phosphate pathway in the flight muscles of hummingbirds? Glucose 6-phosphate is converted to ribose 5-phosphate. Glucose 6-phosphate is converted to carbon dioxide. Glucose 6-phosphate is converted to carbon dioxide and pyruvate. Glucose 6-phosphate is converted to carbon dioxide and ribose 5-phosphate.

Answer 1

GLUCOSE-6-PHOSPHATE IS CONVERTED TO CARBON DIOXIDE AND RIBOSE 5- PHOSPHATE

Step-by-step explanation:

Glucose-6-phosphate that enters the pentose phosphate pathway are converted into a five carbon sugar called ribulose-5-phosphate and carbon dioxide is released. In this pathway, glucose-6-phosphate is converted to 6-phosphoglucono lactone by an enzyme called glucose-6-phosphate dehydrogenase. NADPH is formed as a byproduct of the oxidation of glucose-6-phosphate to the lactone compound. Lactonase, an enzyme uses water to form 6-phosphogluconate from 6-phosphogluconolactone which is further hydrolyzed and decarboxylated (that is a carbon atom is removed) into ribulose-5-phosphate and carbon dioxide by 6-phosphogluconate dehydrogenase. These processes are involved in the flight muscles of hummingbirds for production of energy from NADPH and for the fight against oxygen crime as NADPH readily donate its electrons to antioxidants in the body to fight oxygen deficiency.