Question

911!!! please answer this!!!

Answer 1

Explanation:

Fourth option

Answer 2

`\left((3a^(-3)b^2)/(2a^(-1)b^0)\right)^2`

First some simplifying:

`\left((3a^1b^2)/(2a^3b^0)\right)^2=\left((3b^2)/(2a^2)\right)^2=(9b^4)/(4a^4)`

Then with
`a=-2` and
`b=-3`, we have
`a^4=(-2)^4=16=4^2` and
`b^4=(-3)^4=81=9^2`, so

`(9b^4)/(4a^4)=(9\cdot9^2)/(4\cdot4^2)=(9^3)/(4^3)=(729)/(64)`