Given:
Let us assume that E,F,G,H be the points at which the circle touches the line segment AB, BC, CD, DA.
The length of EB = 9.6 units.
The length of AH = 3.7 units.
The length of CD = 12 units.
We need to determine the perimeter of ABCD.
Lengths of sides of the quadrilateral ABCD:
Let CG = x, then DG = 12 - x
We know the property the property that "if the lengths of the two tangents drawn from an exterior point to a circle are equal".
Hence, applying the property, we have;
AH = AE = 3.7 units.
EB = BF = 9.6 units.
CG = CF = x units.
DG = DH = (12 - x) units.
Perimeter of quadrilateral ABCD:
The perimeter of ABCD can be determined by adding all the lengths of the sides of the quadrilateral ABCD.
Thus, we have;
![Perimeter=AE+EB+BF+FC+CG+GD+DH+AH](https://img.qammunity.org/2021/formulas/mathematics/high-school/8jtmy3bhiewy8j1dgbsxof15yvlbjdtdcc.png)
Substituting the values, we have;
![Perimeter=3.7+9.6+9.6+x+x+12-x+12-x+3.7](https://img.qammunity.org/2021/formulas/mathematics/high-school/ckdgctrsh8u08q6reso13kt05s3g1zj7yb.png)
![Perimeter=50.6](https://img.qammunity.org/2021/formulas/mathematics/high-school/2m180m8k28gp96266xt5wmd82q6h06q90n.png)
Thus, the perimeter of the quadrilateral ABCD is 50.6 units.