Question

Please help

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313K.

Thank you

Answer 1

c = .137 J/g

Step-by-step explanation:

q = mcΔT, where q=heat, m=mass, c=specific heat, ΔT=change in temp.

q = 96 J

m = 35 g

c = ?

ΔT = Tfinal - Tinitial = 313 - 293 K = 20 K

q = mcΔT

96 = 35c*20

96 = 700c

c = .137 J/g