16,834 views
3 votes
3 votes
F(x)=2x^3-6x+k and the remainder when f(x) is divided by x+1=7 then what is the value of k

User Frntn
by
2.3k points

1 Answer

14 votes
14 votes

Given: f(x)=2x(cube)-6x+x

reaminder of f(x) when (x+1) diveded

to find value of k

solution,

f(x)=2x(cube)-6x+k

f(-1)=7

2(-1)(cube)+6+k=7

4+x=7

k=7

Hence,k=7

User Doncoleman
by
3.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.