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36 votes
36 votes
What is the radius of a sphere with a volume of 802m3 to the nearest tenth of a meter?

User Slellis
by
2.6k points

2 Answers

17 votes
17 votes

Answer:

r = 5.8 meters

Explanation:

The volume formula is V = (4/3)(pi)(r^3), where r is the radius.

Solving for r, we get first 3V = (4pi)(r^3), so that r^3 = (3V)/(4pi)

or in this case, r^3 = 3(802 m^3) / (4pi) = 191.5 meters^3

Taking the cube root of both sides yields r = 5.8 meters

User Laura Paakkinen
by
2.8k points
22 votes
22 votes

Sphere

Solve for radius

r≈5.76m

V Volume

802

r

d

r

d

d

r

Using the formula

V=4

3πr3

Solving forr

r=(3V

4π)⅓=(3·802

4·π)⅓≈5.76362m

User Verdammelt
by
3.3k points