Question

Suppose you walk into a sauna that has an ambient temperature of 48.0°C. (a) Calculate the rate of heat transfer in watts to you by radiation given your skin temperature is 37.0°C, the emissivity of skin is 0.98, and the surface area of your body is 1.30 m2.

Answer 1

Answer:99.84 W

Step-by-step explanation:

Given

Ambient temperature
`T_(\infty )=48^(\circ)C\approx 321\ K`

Temperature of skin
`T=37^(\circ)C\approx 310\ K`

Skin emissivity
`\epsilon =0.98`

Surface area
`A=1.30\ m^2`

Rate of heat transfer is
`Q=\epsilon A\sigma (T_0^4-T^4)`

`Q=0.98* 1.30* 5.67* 10^(-8)((321)^4-(310)^4)`

`Q=99.84\ W`