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Solve for variables 2x+y=0 5x+3y=2

User Linuts
by
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2 Answers

2 votes

Answer: x= -2 and y= 4

Explanation:

Let's solve your system by substitution.

2x+y=0;5x+3y=2

Step: Solve 2x+=0 for y:

2x+y=0

2x+y+−2x=0+−2x (Add -2x to both sides)

y = −2x

Step: Substitute −2x for y in

5x+3y=2:

5x+3y=2

5x+3−2x=2

-x=2 (Simplify both sides of the equation)

−x/−1=2/-1 (Divide both sides by -1)

x=−2

Step: Substitute −2for x in y=−2x:

y=−2x

y =(−2)(−2)

y=4 (Simplify both sides of the equation)

Answer:

x=−2 and y=4

User Thanu
by
8.0k points
4 votes

Answer:

Explanation:

rearrange to get y=

y=-2x

substitue into:

5x +3(-2x) =2

5x -6x =2

-x = 2

therefore x=-2

5(-2) +3y =2

-10 +3y=2

3y = 12

y = 4

hope this helps!

User Perigrin
by
8.2k points

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